MATH POLICE, REPORTING FOR DUTY
Combinatorics are not my strong suit (I’m more of a physics/calculus person), so please point out any mistakes I make. Lets assume that the draw was random each time and calculate the probability of none of the next draws being exactly the replaced card. I will be generous and assume that no additional card draw happens and the average game lasts 8 or so turns. In this hypothetical situation, the player replaced once each turn and draws no additional cards. Also, I will be considering the case where you draw EXACTLY the card you replaced, not another copy of the same card.
Since you draw 5 at the start of the game, the starting deck size is 34 cards. When you replace a card, your deck size does not decrease. Now, the deck contains 33 regular cards and 1 freshly replaced card. As such, the probability of not that freshly replaced card is 33/34.
On the next turn, a similar situation occurs. Now, the deck contrains 32 regular cards and 1 freshly replaced card after you replace. No, the probability of drawing a regular card is 32/33
So, the probability of NOT drawing a freshly replaced card in an 8 turn game is
(33-0)/(34-0) * (33-1)/(34-1)…(33-7)/(34-7)= 0.7647
Which is equal to about 0.7647, which is very close to 75%. In other wards, around every 1/4 games, it is expected that you will draw the exact same card you replaced on that turn at least once in one game. This is far from improbably and does not even factor multiple copies of the same card in the deck. This around 25% chance of this happening at least once each game combined with conformation bias (people remembering the times where it did happen over the times where it did not) probably spawned these threads
Now, onto the next phase. I’m still working on this, but I’m playing a 1-of-each deck in practice mode and recording my replaces to see if the result matches these numbers. So far, this theory looks like it’s to be debunked.